南阳oj 题目217 a letter and a number

a letter and a number

时间限制：3000 ms  |  内存限制：65535 KB
难度：1

描述we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;

Give you a letter x and a number y , you should output the result of y+f(x).

输入On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
输出for each case, you should the result of y+f(x) on a line
样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

注：此题为：南阳oj 题目217 a letter and a number

说明：用scanf读入时,注意回车键也是字符，要加    getchar();  吸收回车；

已AC源代码：

#include<stdio.h>
char ch1[]="0ABCDEFGHIJKLMNOPQRSTUVWXYZ";
char ch2[]="0abcdefghijklmnopqrstuvwxyz";
int yjj(char ch)
{
int i,x;
for(i=1;i<=26;++i)
{
if(ch==ch1[i])
{
x=i; break;
}
if(ch==ch2[i])
{
x=(-1)*i; break;
}
}
return x;
}
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
getchar();
char c;
int y,x,sum;
scanf("%c %d",&c,&y);
x=yjj(c);
sum=x+y;
printf("%d\n",sum);
}
return 0;
}