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关于求最大公约数和最小公倍数的的算法

2013-07-02 22:26 295 查看
#include<cstdio>
int main()
{
  int a,b,num1,num2,temp;
  printf("请输入两个整数:\n");
  scanf("%d  %d",&num1,&num2);
  if(num1<num2)/*交换两个数,使大数放在num1上*/
  {
    temp=num1;
    num1=num2;
    num2=temp;
  }

  a=num1;b=num2;
  while(b!=0)/*利用辗除法,直到b为0为止*/
  {
    temp=a%b;
    a=b;
    b=temp;
  }
  printf("最大公约数:%d\n",a);
  printf("最小公倍数:%d\n",num1*num2/a);
  return 0;
}


#include<cstdio>
int num1,num2;

void swap(int &a,int &b)
{
    if(a<b)
    {
        int temp = b;
        b = a;
        a = temp;
    }
}

int gcd(int a,int b)//greatest common divisor 简称gcd
{
    return (b==0)?a:gcd(b,a%b);
}

int lcm()//Least Common Multiple,简称lcm
{
    return num1*num2/gcd(num1,num2);
}
int main()
{
    printf("请输入两个整数:\n");
    scanf("%d%d",&num1,&num2);

    if(num1<num2)
    swap(num1,num2);

    printf("最大公约数是:%d\n",gcd(num1,num2));
    printf("最大公约数是:%d\n",lcm());
    return 0;
}
#include<cstdio>
int num1,num2;

void swap(int &a,int &b)
{
    if(a<b)
    {
        int temp = b;
        b = a;
        a = temp;
    }
}

int gcd(int a,int b)//greatest common divisor 简称gcd
{
    return (b==0)?a:gcd(b,a%b);
}

int lcm()//Least Common Multiple,简称lcm
{
    return num1*num2/gcd(num1,num2);
}
int main()
{
    printf("请输入两个整数:\n");
    scanf("%d%d",&num1,&num2);

    if(num1<num2)
    swap(num1,num2);

    printf("最大公约数是:%d\n",gcd(num1,num2));
    printf("最大公约数是:%d\n",lcm());
    return 0;
}
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