ZCC loves straight flush HDU - 5228（暴力）

After losing all his chips when playing Texas Hold'em with Fsygd on the way to ZJOI2015, ZCC has just learned a black technology. Now ZCC is able to change all cards as he wants during the game. ZCC wants to get a Straight Flush
by changing as few cards as possible.

We call a five-card hand a Straight Flush when all five cards are consecutive and of the same suit. You are given a five-card hand. Please tell ZCC how many cards must be changed so as to get a Straight Flush.

  

Cards are represented by a letter('A', 'B', 'C', 'D') which denotes the suit and a number('1', '2',⋯⋯,
'13') which denotes the rank.

  

Note that number '1' represents ace which is the largest actually. "1 2 3 4 5" and "10 11 12 13 1" are both considered to be consecutive while "11 12 13 1 2" is not.

InputFirst line contains a single integer T(T=1000)T(T=1000)
which denotes the number of test cases.

For each test case, there are five short strings which denote the cards in a single line. It's guaranteed that all five cards are different.OutputFor each test case, output a single line which is the answer.Sample Input

3
A1 A2 A3 A4 A5
A1 A2 A3 A4 C5
A9 A10 C11 C12 C13

Sample Output

0
1
2

题意：枚举各种类型的同花顺，遍历看有几个存在的不存在的就是需要修改的

题目大意：ZCC想要通过更换尽量少的牌得到同花顺。

称五张牌构成了同花顺，当且仅当它们的数值连续，花色一致。请告诉ZCC他至少需要更换多少张牌。

在题目中，牌的花色用一个大写字母('A', 'B', 'C', 'D')来表示，而数值用数字('1', '2', ⋯, '13')来表示。

注意数字1代表ace，在德州扑克中是最大的牌。"1 2 3 4 5" 和 "10 11 12 13 1" 都被认为是连续的。而"11 12 13 1 2"并不是。

并不是很难的一个暴力解法，但是却不好想。

主要就是遍历测试有多少个符合正序，取符合的最大值

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;

int main()
{
int n,t[4][15],ans,q;
char p;
scanf("%d",&n);
getchar();
while(n--)
{
memset(t,0,sizeof(t));
for(int i=1;i<=5;i++)
{
scanf("%c%d",&p,&q);
t[p-'A'][q]=1;//此处对于字符和数字，将字符转化为数字int更为巧妙
getchar();
}
ans=4;
for(int i=0;i<4;i++)
{
for(int j=1;j<=10;j++)
{
q=0;
for(int k=0;k<5;k++)
{
if(t[i][(j+k-1)%13+1])//对于13来说13%13==0所以需要先减一后加一
{
q++;
}
}
ans=min(5-q,ans);
}
}
printf("%d\n",ans);
}
return 0;
}