51Nod－1087－1 10 100 1000

描述

题解

代码

#include <iostream>
#include <cstdio>
#include <cmath>

using namespace std;

int main(int argc, const char * argv[])
{
int T;
int N;

cin >> T;
while (T--)
{
scanf("%d", &N);
double m = sqrt((N - 1) * 2);
if ((int)m * (int)(m + 1) == (N - 1) * 2)
{
printf("1\n");
}
else
{
printf("0\n");
}
}

return 0;
}