leetcode: (70) Climbing Stairs
2015-09-18 18:08
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【Question】
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
可以发现规律nums
=nums[n-1]+nums[n-2];
可以用递归和非递归,使用递归时复杂度较高
下面给出非递归
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
可以发现规律nums
=nums[n-1]+nums[n-2];
可以用递归和非递归,使用递归时复杂度较高
下面给出非递归
class Solution { public: int climbStairs(int n) { if(n==1) return 1; if(n==2) return 2; vector<int> vec(n); vec[0]=1; vec[1]=2; for(int i=2;i<n;i++) { vec[i]=vec[i-1]+vec[i-2]; } return vec[n-1]; } };
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