和为n连续正数序列 【微软面试100题 第五十一题】

#include <iostream>

using namespace std;

void FindContinuousSequence(int n);

int main(void)
{
    int n;
    
    cout << "请输入n:";
    
    cin >> n;
    FindContinuousSequence(n);

    return 0;
}
void Print(int small,int big)
{
    cout << "连续序列有:";
    for(int i = small;i<=big;i++)
        cout << i << " ";
    cout << endl;
}
void FindContinuousSequence(int n)
{
    //因为至少两个正数，1+2=3，因此如果n<3则不存在连续序列
    if(n<3)
        return;
    int small = 1;
    int big = 2;
    //至少两个数，则最小的数肯定小于mid，作为退出while条件
    int mid = (1+n)/2;
    int curSum = small+big;
    while(small<mid)
    {
        if(curSum==n)
            Print(small,big);
        while(curSum>n && small<mid)
        {
            curSum -= small;
            small++;
            if(curSum==n)
                Print(small,big);
        }
        big++;
        curSum += big;
    }
}