您的位置:首页 > 其它

NYOJ 104 矩阵最大和 - 简单动态规划

2013-04-08 08:01 435 查看
//http://acm.nyist.net/JudgeOnline/problem.php?pid=104
#include <queue>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
#define COL nn
#define ROW n
const int M = 1e2 +10;
const int inf = -(1<<30);

int m[M][M];

int main(){
//freopen("in.txt","r",stdin);
//freopen("Input (4).txt","r",stdin);
//freopen("out.txt","w",stdout);
int nn,n,Ncase;cin >> Ncase;
while(Ncase--){
cin >> n >> nn;
for(int i = 1 ; i <= ROW ; i ++){
for(int j = 1 ; j <= COL ; j ++)
scanf("%d",&m[i][j]);
}
for(int i = 1 ; i <= COL ; i++){
for(int j = 2 ; j <= ROW ; j++){
m[j][i] = m[j][i] + m[j-1][i];
}
}
int tmp = inf ,max = inf, sum;
for(int i = 0 ; i <= ROW -1 ; i++){
for(int j = i +1 ; j <= ROW ; j++){
sum = inf;
for(int k = 1 ; k <= COL ; k++){
int tmp = m[j][k] - m[i][k];
sum = ((sum > 0)?(sum):(0)) + tmp;
if(max < sum)
max = sum;
}
}
}
cout << max << endl;
}
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: