Leetcode 342 Power of Four
2017-07-02 16:10
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Leetcode 342 Power of Four
using namespace std;
class Solution {
public:
bool isPowerOfFour(int num) {
if (num > 0 && 1073741824 % num == 0)//是2的幂次
if (num & 0x55555555)//2的幂次数中，4的幂次数，二进制的1都在奇数位上，而其他的像2，8，32这些，二进制的1都在偶数为上（最右一位为第一位）
return true;
return false;
}
};
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