题目1118：数制转换

#include <iostream>
#include <stdio.h>
#include <algorithm>
#include <math.h>
#include <string>
#include <string.h>
#include <vector>
#include <queue>
#include <stack>
#include <sstream>
using namespace std;
//1118
int a,b;
char n[100];
int main(){
    //freopen("input.txt","r",stdin);
    while(scanf("%d %s %d",&a,n,&b)!=EOF){
        int d=0,t;    //将a进制转化为10进制
        for(int i=0;i<strlen(n);i++){
            if(n[i]>='0'&&n[i]<='9') t=n[i]-'0';
            if(n[i]>='a'&&n[i]<='z') t=n[i]-'a'+10;
            if(n[i]>='A'&&n[i]<='Z') t=n[i]-'A'+10;
            d=d*a+t;
        }
        if(d==0) printf("0");
        int k=0;
        while(d>0){
            t=d%b;
            n[k++]=t>=10?'A'+t-10:t+'0';
            d/=b;
        }
        //k--;
       // while(k>=0) printf("%c",n[k--]);
       for(int i=k-1;i>=0;i--)
            printf("%c",n[i]);
       puts("");
    }
    return 0;
}
 
 
/**************************************************************
    Problem: 1118
    User: cust123
    Language: C++
    Result: Accepted
    Time:10 ms
    Memory:1520 kb
****************************************************************/