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guava-retrying重试工具库: 隔多长时间重试

2016-12-27 11:17 323 查看
guava-retrying提供了WaitStrategy接口,用来控制2次重试的时间间隔,这个接口与StopStrategy有的类似。内置的等待策略在WaitStrategies中定义。



import java.io.IOException;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.concurrent.Callable;

public class AlwaysExceptionTask implements Callable<Boolean> {

private static final SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss,SSS");
private int times = 1;

@Override
public Boolean call() throws Exception {
System.out.println(df.format(new Date()));
int thisTimes = times;
times++;

if (thisTimes == 1) {
throw new NullPointerException();
} else if (thisTimes == 2) {
throw new IOException();
} else if (thisTimes == 3) {
throw new ArithmeticException();
} else {
throw new Exception();
}
}
}


WaitStrategies.noWait()失败后立刻重试,没有等待时间。

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(WaitStrategies.noWait())
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new AlwaysExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}

System.out.println("end..." + df.format(new Date()));



WaitStrategies.fixedWait(1, TimeUnit.SECONDS)间隔固定时间之后重试,比如每隔1s重试一次。

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(WaitStrategies.fixedWait(1, TimeUnit.SECONDS))
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new AlwaysExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}



WaitStrategies.randomWait(3, TimeUnit.SECONDS)间隔随机时间后重试,比如间隔0~3中随机时间后重试。

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(WaitStrategies.randomWait(3, TimeUnit.SECONDS))
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new AlwaysExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}

System.out.println("end..." + df.format(new Date()));



WaitStrategies.randomWait(2, TimeUnit.SECONDS, 5, TimeUnit.SECONDS)最小值,最大值之间的随机时间。

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(WaitStrategies.randomWait(2, TimeUnit.SECONDS, 5, TimeUnit.SECONDS))
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new AlwaysExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}

System.out.println("end..." + df.format(new Date()));




WaitStrategies.incrementingWait增量重试,重试的次数越多,等待时间间隔越长。incrementingWait需要传递2个参数,一个是initialSleepTime(第一次到第二次尝试的间隔),一个是increment(每增加一次尝试,需要增加的时间间隔)。第一次尝试是不需要等待的,因为guava-retrying中的第一次尝试,对应正常的第一次调用。从第二次重试开始,第n-1次到n次间隔是:initialSleepTime
+ (n-2)*increment。

1、WaitStrategies.incrementingWait(0, TimeUnit.SECONDS, 0, TimeUnit.SECONDS)等价于     WaitStrategies.noWait()。

2、 WaitStrategies.incrementingWait(1, TimeUnit.SECONDS, 0, TimeUnit.SECONDS)等价于WaitStrategies.fixedWait(1, TimeUnit.SECONDS)

3、 WaitStrategies.incrementingWait(0, TimeUnit.SECONDS, 1, TimeUnit.SECONDS)等价于WaitStrategies.fixedWait(1,
TimeUnit.SECONDS)。



4、  WaitStrategies.incrementingWait(1, TimeUnit.SECONDS, 1, TimeUnit.SECONDS)



WaitStrategies.fibonacciWait()按照斐波那契数列等待。fibonacciWait(long multiplier,long maximumTime,TimeUnit maximumTimeUnit),multiplier单位固定是ms,maximumTime最大等待时间。n=1的时候,是无需等待的。当n>=2的时候,开始符合斐波那契数列。n=2的时候,等待1
* multiplier毫秒;n=3的时候,等待1 * multiplier毫秒;n=4的时候,等待2 * multiplier毫秒;n=5的时候,等待3
* multiplier毫秒;n=6的时候,等待5 * multiplier毫秒;n=7的时候,等待8 * multiplier毫秒;n=8的时候,等待15
* multiplier毫秒;......但是等待时间最长不超过maximumTime。

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(WaitStrategies.fibonacciWait(100, 10, TimeUnit.SECONDS))
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new AlwaysExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}



WaitStrategies.exponentialWait按照指数递增(2的n次方)来等待,各个参数含义与fibonacciWait相同。

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(WaitStrategies.exponentialWait(100, 10, TimeUnit.SECONDS))
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new AlwaysExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}



WaitStrategies.exceptionWait根据抛出的异常来决定等待的时间长短,没有什么实际用处,不过作为学习还是可以了解下,说不定将来能排上用场呢。下面我们定义1个任务,随机抛出不同异常。

class RandomExceptionTask implements Callable<Boolean> {
@Override
public Boolean call() throws Exception {
int round = (int) Math.floor(Math.random() * 8);
System.out.println("round=" + round + ",time=" + df.format(new Date()));
if (round == 1) {
throw new NullPointerException();
} else if (round == 2) {
throw new IOException();
} else if (round == 3) {
throw new ArithmeticException();
} else if (round == 4) {
throw new IllegalStateException();
} else if (round == 5) {
throw new IndexOutOfBoundsException();
} else {
return true;
}
}
}


如果我们希望实现这种效果:如果出现了NullPointerException,那么等待1s后再重试;如果抛出IOException,那等待2s后再重试;如果出现了ArithmeticException,那么等待3s后再重试;如果出现了IllegalStateException,那么等待4s后再重试;如果出现了IndexOutOfBoundsException,那么等待5s后再重试;否则不等待,立刻重试。
// 根据不同异常,等待不同时间后重试
private static <T extends Throwable> Function<T, Long> itsFunction(Class<T> exceptionClass) {
Function<T, Long> result = new Function<T, Long>() {
@Nullable
@Override
public Long apply(@Nullable T input) {
if (input instanceof NullPointerException) {
return 1 * 1000L;
} else if (input instanceof IOException) {
return 2 * 1000L;
} else if (input instanceof ArithmeticException) {
return 3 * 1000L;
} else if (input instanceof IllegalStateException) {
return 4 * 1000L;
} else if (input instanceof IndexOutOfBoundsException) {
return 5 * 1000L;
} else {
return 0L;
}
}
};
return result;
}


下面是测试代码,可以看出不同的异常确实会导致不同的重试间隔。

WaitStrategy exceptionJoin = WaitStrategies.join(
WaitStrategies.exceptionWait(NullPointerException.class, itsFunction(NullPointerException.class)),
WaitStrategies.exceptionWait(IOException.class, itsFunction(IOException.class)),
WaitStrategies.exceptionWait(ArithmeticException.class, itsFunction(ArithmeticException.class)),
WaitStrategies.exceptionWait(IllegalStateException.class, itsFunction(IllegalStateException.class)),
WaitStrategies.exceptionWait(IndexOutOfBoundsException.class, itsFunction(IndexOutOfBoundsException.class))
);

Retryer<Boolean> retryer = RetryerBuilder.<Boolean>newBuilder()
.retryIfException()
.withWaitStrategy(exceptionJoin)
.build();

System.out.println("begin..." + df.format(new Date()));

try {
retryer.call(new RandomExceptionTask());
} catch (Exception e) {
System.err.println("still failed after retry." + e.getCause().toString());
}

System.out.println("end..." + df.format(new Date()));

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