LeetCode 219. Contains Duplicate II(检查重复)
2016-05-06 07:16
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原题网址:https://leetcode.com/problems/contains-duplicate-ii/
Given an array of integers and an integer k,
find out whether there are two distinct indices i and j in
the array such that nums[i] = nums[j] and
the difference between i and j is
at most k.
方法一:使用哈希映射。
方法二:使用哈希集合。
Given an array of integers and an integer k,
find out whether there are two distinct indices i and j in
the array such that nums[i] = nums[j] and
the difference between i and j is
at most k.
方法一:使用哈希映射。
public class Solution { public boolean containsNearbyDuplicate(int[] nums, int k) { if (nums == null || nums.length <= 1) return false; Map<Integer, Integer> map = new HashMap<>(); map.put(nums[0], 0); for(int i=1; i<nums.length; i++) { Integer prev = map.get(nums[i]); if (prev != null && i-prev<=k) return true; map.put(nums[i], i); } return false; } }
方法二:使用哈希集合。
public class Solution { public boolean containsNearbyDuplicate(int[] nums, int k) { if (nums == null || nums.length <= 1 || k <= 0) return false; Set<Integer> set = new HashSet<>(); for(int i=0; i<nums.length; i++) { if (i>k) set.remove(nums[i-k-1]); if (!set.add(nums[i])) return true; } return false; } }
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