(Leetcode)11. Container With Most Water
2016-05-04 21:22
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题目:
Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
题意:
找到条纵线然后这两条线以及X轴构成的容器能容纳最多的水。
思路:
面积,它受长和高的影响,当长度减小时候,高必须增长才有可能提升面积,所以我们从长度最长时开始递减,然后寻找更高的线来更新候补;
Given n non-negative integers a1, a2, …, an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
题意:
找到条纵线然后这两条线以及X轴构成的容器能容纳最多的水。
思路:
面积,它受长和高的影响,当长度减小时候,高必须增长才有可能提升面积,所以我们从长度最长时开始递减,然后寻找更高的线来更新候补;
public int maxArea(int[] height) { int left = 0; int right = height.length-1; int area = 0 ; while(left<right){ area = Math.max(area, Math.min(height[left], height[right])*(right-left)); if(height[left]<height[right]){ left ++; } else{ right --; } } return area; }
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