DAY6：leetcode #11 Container With Most Water

Given n non-negative integers a1, a2,
..., an, where each represents a point at coordinate (i, ai). n vertical
lines are drawn such that the two endpoints of line i is at (i, ai) and (i,
0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

一开始用了两层循环遍历的思路，超时。看到了这样的思路：采用两个指针l和r，初始化分别指向数组的两端，然后在向中间移动找到最大容量。如果l指向的数字小，则l需要右移才有可能获得更大容量，因为此时如果左移r，得到的容量肯定比左移r之前的容量小（高度已经被较小的l限制住了）。如果r指向的数字小，则需要左移r。这样，当l和r相遇的时候，最大的容量就是我们需要的。

class Solution(object):
def maxArea(self, height):
"""
:type height: List[int]
:rtype: int
"""
max_v = 0
i = 0
j = len(height) - 1
while True:
if max_v < (j-i)*min(height[i],height[j]):
max_v = (j-i)*min(height[i],height[j])
if height[i] < height[j]:
i += 1
else:
j -= 1
if i == j:
break
return max_v