A. Gabriel and Caterpillar(cf)

A. Gabriel and Caterpillar

time limit per test
1 second

memory limit per test
256 megabytes

input
standard input

output
standard output

The 9-th grade student Gabriel noticed a caterpillar on a tree when walking around in a forest after the classes. The caterpillar was on the heighth1 cm from
the ground. On the heighth2 cm (h2 > h1) on the same tree hung an apple and
the caterpillar was crawling to the apple.

Gabriel is interested when the caterpillar gets the apple. He noted that the caterpillar goes up bya cm per hour by day and slips down by
b cm per hour by night.

In how many days Gabriel should return to the forest to see the caterpillar get the apple. You can consider that the day starts at10 am and finishes at
10 pm. Gabriel's classes finish at2 pm. You can consider that Gabriel noticed the caterpillar just after the classes at2 pm.

Note that the forest is magic so the caterpillar can slip down under the ground and then lift to the apple.

Input
The first line contains two integers h1, h2 (1 ≤ h1 < h2 ≤ 105)
— the heights of the position of the caterpillar and the apple in centimeters.

The second line contains two integers a, b (1 ≤ a, b ≤ 105) — the distance the caterpillar goes up by day and slips down by night,
in centimeters per hour.

Output
Print the only integer k — the number of days Gabriel should wait to return to the forest and see the caterpillar getting the apple.

If the caterpillar can't get the apple print the only integer
 - 1.

Examples

Input

10 30
2 1

Output

1

Input

10 13
1 1

Output

0

Input

10 19
1 2

Output

-1

Input

1 505 4

Output

1

Note
In the first example at 10 pm of the first day the caterpillar gets the height26. At
10 am of the next day it slips down to the height14. And finally at
6 pm of the same day the caterpillar gets the apple.

Note that in the last example the caterpillar was slipping down under the ground and getting the apple on the next day.

AC代码

#include <iostream>

#include <cstdio>

using namespace std;

int main()

{

int h1, h2, a, b, day = 0;

scanf("%d%d%d%d", &h1, &h2, &a, &b);

h1 += a*8;

if( h1>=h2 )

printf("0\n");

else

{

day++;

while(1)

{

h1 -= b*12;

h1 += a*12;

if( h1>=h2 )

{

printf("%d\n", day);

break;

}

if( b>=a )

{

printf("-1\n");

break;

}

day++;

}

}

return 0;

}

终于知道为什么说我思路不清晰了，囧死