[Leetcode] Longest Consecutive Sequence
2015-10-09 11:11
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Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given
The longest consecutive elements sequence is
Your algorithm should run in O(n) complexity.
将所有element放入set,每check一个element,便找出其所在的最长sequence。并将sequence从set中移除,以免多次check
public class Solution {
public int longestConsecutive(int[] nums) {
Set<Integer> set = new HashSet<>();
int maxlength = 0;
for(int num : nums)
set.add(num);
for(int num : nums){
int length = 1;
int left = num - 1;
int right = num + 1;
while(set.contains(left)){
length++;
set.remove(left);
left--;
}
while(set.contains(right)){
length++;
set.remove(right);
right++;
}
maxlength = Math.max(length, maxlength);
}
return maxlength;
}
}
For example,
Given
[100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is
[1, 2, 3, 4]. Return its length:
4.
Your algorithm should run in O(n) complexity.
将所有element放入set,每check一个element,便找出其所在的最长sequence。并将sequence从set中移除,以免多次check
public class Solution {
public int longestConsecutive(int[] nums) {
Set<Integer> set = new HashSet<>();
int maxlength = 0;
for(int num : nums)
set.add(num);
for(int num : nums){
int length = 1;
int left = num - 1;
int right = num + 1;
while(set.contains(left)){
length++;
set.remove(left);
left--;
}
while(set.contains(right)){
length++;
set.remove(right);
right++;
}
maxlength = Math.max(length, maxlength);
}
return maxlength;
}
}
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