PAT (Advanced Level) 1058. A+B in Hogwarts (20) 字符串相加
2015-07-27 21:11
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If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
Sample Output:
compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
简单的字符串相加。/*2015.7.27cyq*/ #include <iostream> using namespace std; int main(){ int a1,b1,c1,a2,b2,c2; scanf("%d.%d.%d",&a1,&b1,&c1); scanf("%d.%d.%d",&a2,&b2,&c2); int a,b,c,carry; c=(c1+c2)%29; carry=(c1+c2)/29; b=(b1+b2+carry)%17; carry=(b1+b2+carry)/17; a=a1+a2+carry; printf("%d.%d.%d",a,b,c); return 0; }
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