#leetcode#Longest Consecutive Sqeuence
2015-06-11 12:25
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Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given
The longest consecutive elements sequence is
Your algorithm should run in O(n) complexity.
这题思路和word ladder有异曲同工之妙, 都是抽象成图来用DFS, 每个数字就是顶点, 相邻数字之间有一条边, Code Ganker Rocks!
public class Solution {
public int longestConsecutive(int[] nums) {
if(nums == null || nums.length == 0)
return 0;
int res = Integer.MIN_VALUE;
Set<Integer> set = new HashSet<Integer>();
for(int i : nums){
set.add(i);
}
while(!set.isEmpty()){
Iterator iter = set.iterator();
int item = (Integer)iter.next();
set.remove(item);
int len = 1;
int i = item - 1;
while(set.contains(i)){
len++;
set.remove(i--);
}
i = item + 1;
while(set.contains(i)){
len++;
set.remove(i++);
}
res = Math.max(len, res);
}
return res;
}
}
For example,
Given
[100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is
[1, 2, 3, 4]. Return its length:
4.
Your algorithm should run in O(n) complexity.
这题思路和word ladder有异曲同工之妙, 都是抽象成图来用DFS, 每个数字就是顶点, 相邻数字之间有一条边, Code Ganker Rocks!
public class Solution {
public int longestConsecutive(int[] nums) {
if(nums == null || nums.length == 0)
return 0;
int res = Integer.MIN_VALUE;
Set<Integer> set = new HashSet<Integer>();
for(int i : nums){
set.add(i);
}
while(!set.isEmpty()){
Iterator iter = set.iterator();
int item = (Integer)iter.next();
set.remove(item);
int len = 1;
int i = item - 1;
while(set.contains(i)){
len++;
set.remove(i--);
}
i = item + 1;
while(set.contains(i)){
len++;
set.remove(i++);
}
res = Math.max(len, res);
}
return res;
}
}
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