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isIsomorphic

2015-06-03 00:18 169 查看
超时版:

/*
Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg", "add", return true.

Given "foo", "bar", return false.

Given "paper", "title", return true.

Note:
You may assume both s and t have the same length.*/
import java.util.*;

public class Isomorphic_strings {

public static void main(String[] args)
// TODO Auto-generated method stub
{
System.out.println(isIsomorphic("papera", "titlei"));
/*
* String str="dauqka"; String str1=str.replace('a','x'); str=str1;
* System.out.println(str);
*/

}

public static boolean isIsomorphic(String s, String t) {

int x = 0;
if (s.length() != t.length())
return false;
char[] s_chs = s.toCharArray();
char[] t_chs = t.toCharArray();
for (int i = 0; i < s_chs.length; i++) {
if (!(s_chs[i] == t_chs[i])) {
for (int j = 0; j < i; j++) {
if ((t_chs[j] == t_chs[i]))
x = 1;
}
}
if (x == 0)
t = t.replace(t_chs[i], s_chs[i]);
if (x == 1) {
t_chs[i] = s_chs[i];
t = String.valueOf(t_chs);

}
t_chs = t.toCharArray();
}

return (s.equals(t));

}

}


AC

public static boolean isIsomorphic(String s, String t) {

Map<Character, Character> hm = new HashMap<Character, Character>();
if (s.length() != t.length())
return false;
char[] s1 = s.toCharArray();
char[] t1 = t.toCharArray();
for (int i = 0; i < s1.length; i++) {
if (hm.containsKey(s1[i])) {
if ((t1[i] != hm.get(s1[i])))
return false;
}
hm.put(s1[i], t1[i]);
}

return true;
}

}
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