LeetCode: Container With Most Water
2015-02-11 15:21
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Given n non-negative integers a1, a2,
..., an, where each represents a point at coordinate (i, ai). n vertical
lines are drawn such that the two endpoints of line i is at (i, ai) and (i,
0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
Round 2:
class Solution {
public:
int maxArea(vector<int> &height) {
int left = 0, right = height.size()-1;
int max = INT_MIN;
while(left < right)
{
max = std::max(max, (right-left) * std::min(height[left], height[right]));
if(height[left] > height[right])
right--;
else
left++;
}
return max;
}
};
..., an, where each represents a point at coordinate (i, ai). n vertical
lines are drawn such that the two endpoints of line i is at (i, ai) and (i,
0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
class Solution { public: int maxArea(vector<int> &height) { int start = 0, end = height.size()-1; int max = INT_MIN; while(start < end) { int cur = std::min(height[start], height[end]) * (end - start); max = std::max(max, cur); if(height[start] <= height[end]) start++; else end--; } return max; } };
Round 2:
class Solution {
public:
int maxArea(vector<int> &height) {
int left = 0, right = height.size()-1;
int max = INT_MIN;
while(left < right)
{
max = std::max(max, (right-left) * std::min(height[left], height[right]));
if(height[left] > height[right])
right--;
else
left++;
}
return max;
}
};
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