杭电 2057 A+B Again(睡前一水--16进制控制)

A + B Again

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 15226 Accepted Submission(s): 6642



Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.

Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.

Easy ? AC it !


Input
The input contains several test cases, please process to the end of the file.

Each case consists of two hexadecimal integers A and B in a line seperated by a blank.

The length of A and B is less than 15.


Output
For each test case,print the sum of A and B in hexadecimal in one line.



Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

Sample Output

0
2C
11
-2C
-90
/*
16进制X x 控制输出的大小写，并且负数表示方法不是用的 -
Time:2014-9-5 19:50
*/
#include<cstdio>
#include<cstring>
#include<cmath>
#include <cstdlib>
void solve(){
	__int64 a,b;
	while(scanf("%I64X%I64X",&a,&b)!=EOF){
		a+=b;
		if(a<0){
		printf("-%I64X\n",-a);
		}else
		printf("%I64X\n",a);
	}
}
int main(){
	solve();
return 0;
}