uva 424 Integer Inquiry (大数加法)
2014-08-07 10:13
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``This supercomputer is great,'' remarked Chip. ``I only wish Timothy were here to see these results.'' (Chip moved to a new apartment, once one became available on the third floor of the Lemon Sky apartments on
Third Street.)
Input
The input will consist of at most 100 lines of text, each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length, and will only contain digits (no VeryLongIntegerwill be negative).
The final input line will contain a single zero on a line by itself.
Output
Your program should output the sum of the VeryLongIntegers given in the input.Sample Input
123456789012345678901234567890 123456789012345678901234567890 123456789012345678901234567890 0
Sample Output
370370367037037036703703703670
题解----就是用数组模拟每位相加,最后再进位,注意数组不要从0,1,2,3开始存, 进位可能需要前面的空间 #include<iostream> #include<cstdio> #include<cstring> using namespace std; int a[105],b[105]; char str[105]; void atoi(char c[])//用数组存每一位 { int p,i; for(i=strlen(c)-1,p=104;i>=0;i--,p--) { b[p]=c[i]-'0'; } } int main() { int i,q=0; memset(a,0,sizeof(a)); while(cin>>str) { memset(b,0,sizeof(b)); if(strcmp(str,"0")==0) break; atoi(str); for(i=104;i>=0;i--) { a[i]=b[i]+a[i]; } } for(i=104;i>=0;i--) { a[i-1]=a[i-1]+a[i]/10;//进位 a[i]=a[i]%10;//余数 } for(i=0;i<105;i++) { if(a[i]==0&&q==0) continue; else { cout<<a[i]; q=1; } } puts(""); return 0; }
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