您的位置:首页 > 其它

【二叉树的递归】05二叉树中找任意起点和终点使他们的路径和最大【Binary Tree Maximum Path Sum】

2014-04-08 17:01 507 查看
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++给定一个二叉树,寻找值最大的路径。这个路径可以从这个树上面的任意一个节点开始,然后在任意一个节点结束。例如:给定下面的二叉树,
1
/\
23

返回
6
.++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++Givenabinarytree,findthemaximumpathsum.Thepathmaystartandendatanynodeinthetree.Forexample:
Giventhebelowbinarytree,
1
/\
23

Return
6
.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

test.cpp:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
2425
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
#include<iostream>
#include<cstdio>
#include<stack>
#include<vector>
#include"BinaryTree.h"usingnamespacestd;/**
*Definitionforbinarytree
*structTreeNode{
*intval;
*TreeNode*left;
*TreeNode*right;
*TreeNode(intx):val(x),left(NULL),right(NULL){}
*};
*/
intmax_sum;
intdfs(constTreeNode*root)
{
if(root==NULL)
{
return0;
}
intl=dfs(root->left);
intr=dfs(root->right);
intsum=root->val;
if(l>0)
{
sum+=l;
}
if(r>0)
{
sum+=r;
}
max_sum=max(max_sum,sum);
returnmax(r,l)>0?max(r,l)+root->val:root->val;
}
intmaxPathSum(TreeNode*root)
{max_sum=-0xffff;
dfs(root);
returnmax_sum;
}//树中结点含有分叉,
//8
///\
//61
///\
//92
///\
//47
intmain()
{
TreeNode*pNodeA1=CreateBinaryTreeNode(8);
TreeNode*pNodeA2=CreateBinaryTreeNode(6);
TreeNode*pNodeA3=CreateBinaryTreeNode(1);
TreeNode*pNodeA4=CreateBinaryTreeNode(9);
TreeNode*pNodeA5=CreateBinaryTreeNode(2);
TreeNode*pNodeA6=CreateBinaryTreeNode(4);
TreeNode*pNodeA7=CreateBinaryTreeNode(7);ConnectTreeNodes(pNodeA1,pNodeA2,pNodeA3);
ConnectTreeNodes(pNodeA2,pNodeA4,pNodeA5);
ConnectTreeNodes(pNodeA5,pNodeA6,pNodeA7);PrintTree(pNodeA1);cout<<maxPathSum(pNodeA1)<<endl;DestroyTree(pNodeA1);
return0;
}
结果输出:

24
BinaryTree.h:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
#ifndef_BINARY_TREE_H_
#define_BINARY_TREE_H_structTreeNode
{
intval;
TreeNode*left;
TreeNode*right;
TreeNode(intx):val(x),left(NULL),right(NULL){}
};TreeNode*CreateBinaryTreeNode(intvalue);
voidConnectTreeNodes(TreeNode*pParent,
TreeNode*pLeft,TreeNode*pRight);
voidPrintTreeNode(TreeNode*pNode);
voidPrintTree(TreeNode*pRoot);
voidDestroyTree(TreeNode*pRoot);#endif/*_BINARY_TREE_H_*/
BinaryTree.cpp:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
2425
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
#include<iostream>
#include<cstdio>
#include"BinaryTree.h"usingnamespacestd;/**
*Definitionforbinarytree
*structTreeNode{
*intval;
*TreeNode*left;
*TreeNode*right;
*TreeNode(intx):val(x),left(NULL),right(NULL){}
*};
*///创建结点
TreeNode*CreateBinaryTreeNode(intvalue)
{
TreeNode*pNode=newTreeNode(value);returnpNode;
}//连接结点
voidConnectTreeNodes(TreeNode*pParent,TreeNode*pLeft,TreeNode*pRight)
{
if(pParent!=NULL)
{
pParent->left=pLeft;
pParent->right=pRight;
}
}//打印节点内容以及左右子结点内容
voidPrintTreeNode(TreeNode*pNode)
{
if(pNode!=NULL)
{
printf("valueofthisnodeis:%d\n",pNode->val);if(pNode->left!=NULL)
printf("valueofitsleftchildis:%d.\n",pNode->left->val);
else
printf("leftchildisnull.\n");if(pNode->right!=NULL)
printf("valueofitsrightchildis:%d.\n",pNode->right->val);
else
printf("rightchildisnull.\n");
}
else
{
printf("thisnodeisnull.\n");
}printf("\n");
}//前序遍历递归方法打印结点内容
voidPrintTree(TreeNode*pRoot)
{
PrintTreeNode(pRoot);if(pRoot!=NULL)
{
if(pRoot->left!=NULL)
PrintTree(pRoot->left);if(pRoot->right!=NULL)
PrintTree(pRoot->right);
}
}voidDestroyTree(TreeNode*pRoot)
{
if(pRoot!=NULL)
{
TreeNode*pLeft=pRoot->left;
TreeNode*pRight=pRoot->right;deletepRoot;
pRoot=NULL;DestroyTree(pLeft);
DestroyTree(pRight);
}
}

















                                            
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: