uva10003 - Cutting Sticks(DP,区间)
2013-05-04 19:54
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Time limit: 3.000 seconds |
dp[a][b]=min(dp[a][k]+dp[k][b])+ab段长度。k为ab段中的切点。
#include<iostream> #include<cstring> #include<cstdio> using namespace std; const int mm=55; const int oo=1e9; int f[mm]; int dp[mm][mm];///a到b之间的最优值 int ans; int DP(int a,int b) { if(dp[a][b])return dp[a][b]; if(a==b-1)return 0;///就一段 int _min=oo; for(int i=a+1;i<b;++i) { _min=std::min(_min,DP(a,i)+DP(i,b)); } dp[a][b]=_min+f[b]-f[a]; return dp[a][b]; } int main() { int len,n; while(~scanf("%d",&len)&&len) { ans=0;scanf("%d",&n); memset(dp,0,sizeof(dp)); for(int i=1;i<=n;++i) scanf("%d",&f[i]); f[0]=0;f[n+1]=len; printf("The minimum cutting is %d.\n",DP(0,n+1)); } }
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