python list转换字符串报错TypeError: sequence item 0: expected str instance, int found

python list转换字符串报错TypeError: sequence item 0: expected str instance, int found

场景：将列表转化为指定分隔符的字符串，列表当中有数字时会报如上错误。

user.txt:
alex:202cb962ac59075b964b07152d234b70:1234:0
tom:202cb962ac59075b964b07152d234b70:2234:0
test01:202cb962ac59075b964b07152d234b70::0

d_user内容如下：
{'alex': ['alex', '202cb962ac59075b964b07152d234b70', '1234', '0'], 'tom': ['tom', '202cb962ac59075b964b07152d234b70', '2234', '0'], 'test01': ['test01', '202cb962ac59075b964b07152d234b70', '', '0']}

>>> l1 = ['alex', '202cb962ac59075b964b07152d234b70', '1234', 0]
'0'

>>> ':'.join(l1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: sequence item 3: expected str instance, int found

解决办法：

>>> ':'.join('%s' %i for i in l1)
'alex:202cb962ac59075b964b07152d234b70:1234:0'

def dolock(username):
file_content = ""
d_user[username][3] = 1
for k in d_user:
file_content += ':'.join(d_user[k]) + '\n'
with open(user_file,'r+') as ufile:
ufile.write(file_content)

def dolock(username):
file_content = ""
d_user[username][3] = 1
for k in d_user:
file_content += ':'.join('%s' %i for i in d_user[k]) + '\n'
with open(user_file,'r+') as ufile:
ufile.write(file_content)

转载于:https://www.cnblogs.com/pyops/articles/9752075.html

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