TypeError: sequence item 0: expected str instance, int found的解决办法
2017-09-30 12:34
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TypeError: sequence item 0: expected str instance, int found
小例子：
a = ['1','2','3',1]
print(' '.join(a))以为会打印 1 2 3 1
结果报了错
Traceback (most recent call last):
File "C:/Users/Administrator/Desktop/onetest.py", line 188, in <module>
print(' '.join(a))
TypeError: sequence item 3: expected str instance, int found上网查了资料，说list包含数字，不能直接转化成字符串。
解决办法：
print(" ".join('%s' %id for id in list1))即遍历list的元素，把他转化成字符串。这样就能成功输出1 2 3 1了。
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