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第4届CCCC字符串大赛 L2-1特立独行的幸福

2019-03-31 15:34 134 查看
/*题解详见公众号文章,最底扫码关注*/
#include<iostream>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<string>
#include<cstdlib>
#include<cstdio>
#include<map>
#include<vector>
#include<set>
#include<queue>
#include<stack>
using namespace std;
typedef long long ll;
const ll mod = 1e9 + 7;
const int N = 1e6 + 7;
#define IO do{\
ios::sync_with_stdio(false);\
cin.tie(0);\
cout.tie(0);}while(0)
#define mem(a,b) memset(a,b,sizeof(a));
map<int, int>d;
int su[10005] = {1,1,0};
void isprime()
{
for (int i = 2; i < 10005; i++)
if (!su[i])
for (int j = i*i; j < 10005; j += i)
su[j] = 1;
}
int main()
{
int n, m;
cin >> n >> m;
int b[10005], l[10005],c=0,dd[5];
isprime();
for (int i = n; i <= m; i++)
{
int a = i,cc=0,flag1=0;
while (a != 1)
{
cc++;
dd[0] = a / 10000;
dd[1] = a / 1000 % 10;
dd[2] = a / 100 % 10;
dd[3] = a / 10 % 10;
dd[4] = a % 10;
a = dd[0] * dd[0] + dd[1] * dd[1] + dd[2] * dd[2] + dd[3] * dd[3] + dd[4] * dd[4];
if (cc > 10)
{
flag1 = 1;
break;
}
}
if (!flag1)
{
l[c] = cc;
b[c++] = i;
}
}
for (int i = 0; i < c; i++)
{
int a = b[i], flag1 = 0;
while (a != 1)
{
dd[0] = a / 10000;
dd[1] = a / 1000 % 10;
dd[2] = a / 100 % 10;
dd[3] = a / 10 % 10;
dd[4] = a % 10;
a = dd[0] * dd[0] + dd[1] * dd[1] + dd[2] * dd[2] + dd[3] * dd[3] + dd[4] * dd[4];
d[a]++;
}
}
int flag1 = 0;
for (int i = 0; i < c; i++)
{
int a = b[i];
if (d.count(a) && (a >= n&& a <= m))
continue;
else
{
flag1++;
cout << a << " ";
if (su[a])
cout << l[i] << endl;
else
cout << 2 * l[i] << endl;
}
}
if (!flag1)
cout << "SAD" << endl;
return 0;
}

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