Python 如何对含有重复列表的列表求集合？

在Python的编程中，我们希望简约含有重复列表的列表，即对含有重复列表的列表求其集合，这个需求还是比较常见的。例如：L = [['Banana'],['Orange'],['Orange'],['Orange'],[],[],[],['Mango','Strawberry'],['Apple'],['Mango', 'Strawberry'], ['Mango','Strawberry']]我们想求这类列表的集合，如果直接用set命令，会得到TypeError的错误。>>> L[['Banana'], ['Orange'], ['Orange'], ['Orange'], [], [], [], ['Mango', 'Strawberry'], ['Apple'], ['Mango', 'Strawberry'], ['Mango', 'Strawberry']]>>> set(L) Traceback (most recent call last):  File "<pyshell#86>", line 1, in <module>    set(L)TypeError: unhashable type: 'list' 为了删除重复的列表，每个列表仅保留一个,我编写如下的程序： # Author:Li Xing Mar 2nd,2018# Simplied the multi-listsdef list_simplied(org_lst):     lst_len = len(org_lst)     if lst_len == 0 or lst_len == 1:         return org_lst     else:         simplied_lst = []         repeated_index =[]         for i in range(lst_len):             if i in repeated_index:                 continue             else:                 temp = org_lst[i]                 for j in range(i+1,lst_len):                     if org_lst[j] == temp:                         repeated_index.append(j)                 simplied_lst.append(temp)         return simplied_lst>>> list_simplied(L)[['Banana'], ['Orange'], [], ['Mango', 'Strawberry'], ['Apple']]list_simplied函数的对象item，可以是元素、列表、字典等等，例如：>>> lst = [1,1,3,4,5,6,6,6,7]>>> list_simplied(lst)[1, 3, 4, 5, 6, 7]>>> x = [{1:'a',2:'b',3:'c'},{1:'a',2:'b',3:'c'},{},{}]>>> list_simplied(x)[{1: 'a', 2: 'b', 3: 'c'}, {}]喜欢的话，点个赞吧！