[LeetCode] 2. Add Two Numbers 两数相加 @python
2018-03-18 13:59
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[LeetCode] 2. Add Two Numbers 两数相加 @python
Description
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Example Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 Explanation: 342 + 465 = 807.
给定两个非空链表来代表两个非负数,位数按照逆序方式存储,它们的每个节点只存储单个数字。将这两数相加会返回一个新的链表。
你可以假设除了数字 0 之外,这两个数字都不会以零开头。
示例: 输入:(2 -> 4 -> 3) + (5 -> 6 -> 4) 输出:7 -> 0 -> 8 原因:342 + 465 = 807
Solution
添加一个flag,然后链表诸位相加为
tmpsum,若大于
9则
flag为
1,下一位相加时加上
flag。注意最后一位,当最后
flag为
1时,要在结果的表尾加上
1。
# -*- coding: utf-8 -*- """ Created on Sat Mar 17 15:34:35 2018 @author: Saul """ # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def addTwoNumbers(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """ if l1 is None: return l2 if l2 is None: return l1 tmp = ListNode(0) res = tmp flag = 0 while l1 or l2: tmpsum = 0 if l1: tmpsum = l1.val l1 = l1.next if l2: tmpsum += l2.val l2 = l2.next tmpres = ((tmpsum + flag) % 10) flag = ((tmpsum + flag) // 10) res.next = ListNode(tmpres) res = res.next if flag: res.next = ListNode(1) res = tmp.next del tmp return res
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