您的位置:首页 > 其它

LeetCode 2. Add Two Numbers(两数相加)

2016-05-01 07:02 489 查看
原题网址:https://leetcode.com/problems/add-two-numbers/

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)

Output: 7 -> 0 -> 8
方法:按照加法的规则计算。

/**
* Definition for singly-linked list.
* public class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode sum = new ListNode(0);
ListNode current = sum;
int carry = 0;
while (l1 != null || l2 != null || carry != 0) {
if (l1 != null && l2 != null) {
current.next = new ListNode((l1.val + l2.val + carry) % 10);
carry = (l1.val + l2.val + carry) / 10;
l1 = l1.next;
l2 = l2.next;
} else if (l1 != null) {
current.next = new ListNode((l1.val + carry) % 10);
carry = (l1.val + carry) / 10;
l1 = l1.next;
} else if (l2 != null) {
current.next = new ListNode((l2.val + carry) % 10);
carry = (l2.val + carry) / 10;
l2 = l2.next;
} else {
current.next = new ListNode(carry);
carry = 0;
}
current = current.next;
}
return sum.next;
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: