leetcode: 58. Length of Last Word

Problem

# Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
#
# If the last word does not exist, return 0.
#
# Note: A word is defined as a character sequence consists of non-space characters only.
#
# For example,
# Given s = "Hello World",
# return 5.

AC

class Solution():
def lengthOfLastWord(self, s):
return len(s.strip().split(' ')[-1]) if s else 0

if __name__ == "__main__":
assert Solution().lengthOfLastWord("Hello World") == 5
assert Solution().lengthOfLastWord("") == 0