您的位置:首页 > 其它

Leetcode 58. Length of Last Word

2016-09-01 11:39 330 查看
Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s = “Hello World”,

return 5.

思路极其简单的一道题。把代码写优雅简洁,另外第一次 length 忘了初始化导致出错。

class Solution {
public:
int lengthOfLastWord(string s) {
int length=0;
int i=s.size()-1;
while(i>=0 && s[i]==' ')
--i;
if(i==-1)
return 0;
while(i>=0 && s[i--]!=' ')
++length;
return length;
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: