Leetcode 58. Length of Last Word
2016-09-01 11:39
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Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = “Hello World”,
return 5.
思路极其简单的一道题。把代码写优雅简洁,另外第一次 length 忘了初始化导致出错。
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = “Hello World”,
return 5.
思路极其简单的一道题。把代码写优雅简洁,另外第一次 length 忘了初始化导致出错。
class Solution { public: int lengthOfLastWord(string s) { int length=0; int i=s.size()-1; while(i>=0 && s[i]==' ') --i; if(i==-1) return 0; while(i>=0 && s[i--]!=' ') ++length; return length; } };
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