HDOJ 2088 Box of Bricks
2017-10-10 14:45
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HDACM2088
此题只要先求出平均值,然后把低于平均值的个数求出来,并且求和,最后再把average*个数-sum就能得出需要移动的个数,
注意:每两行之间要有一个空行
此题只要先求出平均值,然后把低于平均值的个数求出来,并且求和,最后再把average*个数-sum就能得出需要移动的个数,
注意:每两行之间要有一个空行
import java.util.Scanner; public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); boolean isFirst = true; while(sc.hasNext()){ int n = sc.nextInt(); if (n==0) { break; } if (isFirst) { isFirst = false; }else { System.out.println(); } int[] m = new int ; int sum = 0; for (int i = 0; i < m.length; i++) { m[i] = sc.nextInt(); sum += m[i]; } int average = sum/n; sum = 0; int k = 0; for (int i = 0; i < m.length; i++) { if (m[i]<average) { sum += m[i]; k++; } } System.out.println(average*k-sum); } } }
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