您的位置:首页 > 其它

【jzoj5215】【BZOJ4870】【Shoi2017】【GDOI2018模拟7.9】【组合数问题】【矩阵快速幂】

2017-07-09 16:26 459 查看

题目大意



解题思路

暴力60分没毛病。r

code

#include<cstdio>
#include<cmath>
#include<cstring>
#include<algorithm>
#define LF double
#define LL long long
#define ULL unsigned LL
#define fo(i,j,k) for(LL i=j;i<=k;i++)
#define fd(i,j,k) for(LL i=j;i>=k;i--)
#define fr(i,j) for(LL i=begin[j];i;i=next[i])
using namespace std;
LL max(LL x,LL y){return (x>y)?x:y;}
LL min(LL x,LL y){return (x<y)?x:y;}
LL const mk=50+9,inf=1e18+7;
LL n,p,K,r,ans[mk][mk],mat[mk][mk],tmp[mk][mk];
void multansmat(){
fo(i,0,K-1)fo(j,0,K-1)tmp[i][j]=0;
fo(i,0,K-1)fo(j,0,K-1)fo(k,0,K-1)tmp[i][k]=(tmp[i][k]+ans[i][j]*mat[j][k])%p;
fo(i,0,K-1)fo(j,0,K-1)ans[i][j]=tmp[i][j];
}
void multmatmat(){
fo(i,0,K-1)fo(j,0,K-1)tmp[i][j]=0;
fo(i,0,K-1)fo(j,0,K-1)fo(k,0,K-1)tmp[i][k]=(tmp[i][k]+mat[i][j]*mat[j][k])%p;
fo(i,0,K-1)fo(j,0,K-1)mat[i][j]=tmp[i][j];
}
int main(){
freopen("d.in","r",stdin);
freopen("d.out","w",stdout);
scanf("%lld%lld%lld%lld",&n,&p,&K,&r);
ans[0][0]=1;
fo(i,0,K-1)mat[i][i]++,mat[i][(i+1==K)?0:i+1]++;
LL nk=n*K;
while(nk){
if(nk&1)multansmat();
multmatmat();
nk>>=1;
}
printf("%lld",ans[0][r]);
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: