k-means算法的Python实现
2017-06-06 18:38
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数据集为
1.658985 4.285136 -3.453687 3.424321 4.838138 -1.151539 -5.379713 -3.362104 0.972564 2.924086 -3.567919 1.531611 0.450614 -3.302219 -3.487105 -1.724432 2.668759 1.594842 -3.156485 3.191137 3.165506 -3.999838 -2.786837 -3.099354 4.208187 2.984927 -2.123337 2.943366 0.704199 -0.479481 -0.392370 -3.963704 2.831667 1.574018 -0.790153 3.343144 2.943496 -3.357075 -3.195883 -2.283926 2.336445 2.875106 -1.786345 2.554248 2.190101 -1.906020 -3.403367 -2.778288 1.778124 3.880832 -1.688346 2.230267 2.592976 -2.054368 -4.007257 -3.207066 2.257734 3.387564 -2.679011 0.785119 0.939512 -4.023563 -3.674424 -2.261084 2.046259 2.735279 -3.189470 1.780269 4.372646 -0.822248 -2.579316 -3.497576 1.889034 5.190400 -0.798747 2.185588 2.836520 -2.658556 -3.837877 -3.253815 2.096701 3.886007 -2.709034 2.923887 3.367037 -3.184789 -2.121479 -4.232586 2.329546 3.179764 -3.284816 3.273099 3.091414 -3.815232 -3.762093 -2.432191 3.542056 2.778832 -1.736822 4.241041 2.127073 -2.983680 -4.323818 -3.938116 3.792121 5.135768 -4.786473 3.358547 2.624081 -3.260715 -4.009299 -2.978115 2.493525 1.963710 -2.513661 2.642162 1.864375 -3.176309 -3.171184 -3.572452 2.894220 2.489128 -2.562539 2.884438 3.491078 -3.947487 -2.565729 -2.012114 3.332948 3.983102 -1.616805 3.573188 2.280615 -2.559444 -2.651229 -3.103198 2.321395 3.154987 -1.685703 2.939697 3.031012 -3.620252 -4.599622 -2.185829 4.196223 1.126677 -2.133863 3.093686 4.668892 -2.562705 -2.793241 -2.149706 2.884105 3.043438 -2.967647 2.848696 4.479332 -1.764772 -4.905566 -2.911070
import numpy as np import math def loadData(filename): dataMat = [] #创建一个能装数据的list fr = open(filename) for line in fr.readlines(): curline = line.strip().split('\t')#删除每行最后的换行,以中间的tab分割数据 fltline = list(map(float,curline)) dataMat.append(fltline) dataMat = np.mat(dataMat) #将datMat集合编程ndarray类型存放 return dataMat def disEclud(vecA, vecB): return np.sqrt(np.sum(np.power(vecA - vecB,2))) #计算欧氏距离 def randCent(dataSet,k):#创建随机初始质心 n = np.shape(dataSet)[1] #取得列数 centroids = np.mat(np.zeros((k,n)))#创建一个 K行 n列的0矩阵 for j in range(n):#一列一列的进行随机选取初始化 minJ = np.min().dataset[:,j] #取第J列的最小值 rangeJ = float(np.max(dataSet[:,j]) - minJ) #取最大最小值的差 centroids[:,j] = np.mat(minJ + rangeJ * np.random.rand(k,1)) #创建一个K行1列的向量添加到centroids的第J列上 return centroids def kMeans(dataset,k,disMeas = distEclud, createCent = randCent): m = np.shape(dataset)[0] #取行数 clusterAssment = np.mat(np.zero((m,2))) #创建一个M行2列的0矩阵 该矩阵用来存dataset中每个点属于哪个簇,第二列是到质心的距离 centroids = createCent(dataset,k) clusterChanged = True while clusterChanged: clusterChanged = False for i in range(m): minDist = math.inf #minDist初始化为无穷大 minIndex = -1 # for j in range(k): distJI = disMeas(centroids[j,:],dataset[i,:])#计算 dataset中每个点和质心的距离 if distJI < minDist: minDist = distJI minIndex = j if clusterAssment[i,0] != minIndex: clusterChanged = True clusterAssment[i,:] = minIndex, minDist **2 #将距离最近的点和这个点到质心的距离的平方存入clusterAssment for cent in range(k): ptsInClust = dataset[np.nonzeros(clusterAssment[:,0].A == cent)[0]] #np.nonzeros(clusterAssment[:,0].A == cent)[0]这句代码的意思是 取clusterAssment第1列的值 .A 返回的是matrix object 让其与现在的类型对比,如果相等 #返回clusterAssment的第一列 #dataset把符合条件的样本存入ptsInClust中 centroids[cent,:] = np.mean(prsInClust, axis = 0) #重新计算质心,也就是求各个列的均值。axis= 0 表示列。 return centroids, clusterAssment
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