[leetcode:python]58.Length of Last Word

题目：

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s = “Hello World”,

return 5.

方法一：性能52ms

class Solution(object):
def lengthOfLastWord(self, s):
"""
:type s: str
:rtype: int
"""
if len(s) == 0:
return 0
count = 0
str1 = s.rstrip()
for i in str1:
if i != ' ':
count += 1
else:
count = 0
return count

方法二：性能32ms

class Solution(object):
def lengthOfLastWord(self, s):
"""
:type s: str
:rtype: int
"""
cnt=0
for v in reversed(s):
if v.isspace():
if cnt:break
else:cnt+=1
return cnt

这里的reversed()函数：作用是逆转序列

且reversed()之后，只在第一次遍历时返回值。