[leetcode]Length of Last Word @ Python
2014-06-06 16:49
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原题地址:https://oj.leetcode.com/problems/length-of-last-word/
题意:
Given a string s consists of upper/lower-case alphabets and empty space characters
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
return
解题思路:Python强大的处理字符串的能力。
代码:
题意:
Given a string s consists of upper/lower-case alphabets and empty space characters
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
"Hello World",
return
5.
解题思路:Python强大的处理字符串的能力。
代码:
class Solution: # @param s, a string # @return an integer def lengthOfLastWord(self, s): return len(s.split()[len(s.split())-1]) if s.split() != [] else 0
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