Easy 13 Length of Last Word（58）

Description

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s = “Hello World”,

return 5.

Solution

统计最后一个单词的长度，简单的统计，遇见空格就重新统计。有一点要注意的是，当字符串末尾有空格时，需要保留上一次的长度统计。

class Solution {
public:
int lengthOfLastWord(string s) {
int len=0;
bool flag=true;
for(int i=0;i<s.size();i++){
if(!isspace(s[i])){
if(!flag) len=0;//通过标记位的形式，如果在遇见非空格字符，才清除上次记录。
flag=true;
len++;
}else{
flag=false;
}
}
return len;
}
};