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LeetCode刷题(C++)——Length of Last Word(Easy)

2017-05-14 17:05 423 查看
Given a string s consists of upper/lower-case alphabets and empty space characters 
'
'
, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 

Given s = 
"Hello World"
,

return 
5
.

class Solution {
public:
int lengthOfLastWord(string s) {
if (s.empty())
return 0;
int len = 0;
int k = s.size() - 1;
while (k >= 0 && s[k] == ' ')
k--;
for (int i =k;i >= 0;i--)
{
if (s[i] == ' ')
return len;
len++;
}
return len;
}
};
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