PAT乙级1002题python3代码

目录

目录

PAT乙级1002题python3代码

代码

PAT乙级1002题python3代码

题目：

读入一个自然数n，计算其各位数字之和，用汉语拼音写出和的每一位数字。

输入格式：每个测试输入包含1个测试用例，即给出自然数n的值。这里保证n小于10100。

输出格式：在一行内输出n的各位数字之和的每一位，拼音数字间有1 空格，但一行中最后一个拼音数字后没有空格。

输入样例：

1234567890987654321123456789

输出样例：

yi san wu

代码

# -*- coding: utf-8 -*-
"""
Created on Mon Mar 27 17:00:59 2017

@author: xyq152438
"""
def shuchu(he):   #把he转换成拼音输出，仅可用于最后一个数字
if  he ==0:
print('ling')
elif he == 1:
print('yi')
elif he == 2:
print('er')
elif he == 3:
print('san')
elif he == 4:
print('si')
elif he == 5:
print('wu')
elif he == 6:
print('liu')
elif he == 7:
print('qi')
elif he == 8:
print('ba')
elif he == 9:
print('jiu')

def shuchu_1(he):  #把he转换成拼音输出，不带空格，即不在最后一个数字使用
if  he ==0:
print('ling',end = " ")
elif he == 1:
print('yi',end = " ")
elif he == 2:
print('er',end = " ")
elif he == 3:
print('san',end = " ")
elif he == 4:
print('si',end = " ")
elif he == 5:
print('wu',end = " ")
elif he == 6:
print('liu',end = " ")
elif he == 7:
print('qi',end = " ")
elif he == 8:
print('ba',end = " ")
elif he == 9:
print('jiu',end = " ")

def panduan(shu):     #判断输入的数字
b = list(shu)
he = 0
for i in range(len(b)):   #循环遍历长度，he为各位数字之和
he+=int(b[i])
he_1 =he
if len(b) == 1:
shuchu(he)
else:
for i in range(len(str(he)),0,-1): #倒序遍历he，判断输出条件
if he_1/(pow(10,i-1)) ==0:
if i==1:
print('ling')
else:
print('ling',end=" ")
else:
shuchu_1(int(he_1/(pow(10,i-1))))
he_1-=(int(he_1/(pow(10,i-1))))*(pow(10,i-1))
if i==2:
shuchu(he_1)
break

a = input()
panduan(a)