poj 1125 Stockbroker Grapevine(floyd)
2017-01-29 19:44
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http://blog.csdn.net/lyy289065406/article/details/6645856这个题解题目翻译的很棒。题目很简单
#include <cstdio> #include <cstring> #define INF 999999 #define MAXN 110 int map[MAXN][MAXN]; int n; void floyd() { for(int k = 1; k <= n; ++k) for(int i = 1; i <= n; ++i) for(int j = 1; j <= n; ++j) if(map[i][j] > map[i][k] + map[k][j]) map[i][j] = map[i][k] + map[k][j]; int num; int minute; int res = INF; for(int i = 1; i <= n; ++i) { minute = 0; for(int j = 1; j <= n; ++j) if(minute < map[i][j]) minute = map[i][j]; if(res > minute) { res = minute; num = i; } } if(res < INF) printf("%d %d\n",num,res); else printf("disjoint\n"); } int main() { int pair,minute,num; while(scanf("%d",&n) && n) { for(int i = 1; i <= n; ++i) for(int j = 1; j <= n; ++j) if(i ==j) map[i][j] = 0; else map[i][j] = INF; for(int i = 1; i <= n; ++i) { scanf("%d",&pair); for(int j = 0; j < pair; ++j) { scanf("%d %d",&num,&minute); if(minute < map[i][num]) map[i][num] = minute; } } floyd(); } return 0; }
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