[Leetcode]404. Sum of Left Leaves
2017-01-12 15:07
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题目:
题意: 求二叉树中所有结点的左叶子结点之和
具体代码:
代码中注意的问题:首先要判断节点是不是为空才能进行其他判断,否则就会报空指针异常
题意: 求二叉树中所有结点的左叶子结点之和
具体代码:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public int sumOfLeftLeaves(TreeNode root) { if(root == null){ return 0; } int sum = 0; if (root.left != null && isLeaf(root.left) == true) { sum += root.left.val; } if (root.left != null && isLeaf(root.left) == false) { sum = sum + sumOfLeftLeaves(root.left); } if (root.right != null && isLeaf(root.right) == false) { sum = sum + sumOfLeftLeaves(root.right); } return sum; } public boolean isLeaf(TreeNode root) { if (root != null && root.right == null && root.left == null) { return true; } else { return false; } } }
代码中注意的问题:首先要判断节点是不是为空才能进行其他判断,否则就会报空指针异常
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