玲珑杯”ACM比赛 Round #5 --2的幂次方

1064 - I am Two

Time Limit：1s Memory Limit：64MByte

Submissions：522Solved：205

DESCRIPTION

Check whether an integer n is a power of 2.

INPUT

First line contains a single integer T (T<=20) which denotes the number of test cases. For each test case, there is an 32-bit integer N .

OUTPUT

For each case, output the "Yes" or "No" in a single line.

SAMPLE INPUT

3138

SAMPLE OUTPUT

YesNoYes

SOLUTION

玲珑杯”ACM比赛 Round #5

code：

#include<cstdio>
#include<algorithm>
using namespace std;
int main()
{
int t,n;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
if(n>0&&(n&(n-1))==0)
printf("Yes\n");
else
printf("No\n");
}
return 0;
}