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最长上升子序列(代码实现)

2016-11-09 22:00 381 查看
经典问题,不在赘述

#include <cstdio>
#include <cstring>
const int maxn = 10000;
//用maxlen[i]表示a[1], a[2],..., a[k]中最长上升子序列的长度
//那么状态转移方程为
//maxlen[1] = 1
//maxlen[i] = 1 + MAX{maxlen[j], 其中1 <= j < i, a[j] < a[i]}, (1 < i <= n)
void init(int n, int *a, int *maxlen)
{
memset(maxlen, 0, sizeof(maxlen));
maxlen[1] = 1;
for (int i = 2; i <= n; i++) {
int tem = 0;
for (int j = 1; j < i; j++) {
if (a[j] < a[i] && tem < maxlen[j])
tem = maxlen[j];
}
maxlen[i] = tem + 1;
}

return;
}
//寻找maxlen[maxn]中的最大值
int solve(int n, int *a, int *maxlen)
{
int ans = 0;
for (int i = 1; i <= n; i++)
if (ans < maxlen[i])
ans = maxlen[i];
return ans;
}

int main()
{
freopen("data.in", "r", stdin);
int n;
while (scanf("%d", &n) == 1) {
int a[maxn], maxlen[maxn];
for (int i = 1; i <= n; i++)
scanf("%d", a + i);

init(n, a, maxlen);
int ans = solve(n, a, maxlen);

printf("%d\n", ans);
}

return 0;
}
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