LeetCode 387 First Unique Character in a String
2016-08-26 11:10
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Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
Examples:
Note: You may assume the string contain only lowercase letters.
Runtime: 16
ms
public int firstUniqChar(String s) {
int[] count = new int[26];
char[] chars = s.toCharArray();
for (int i = 0; i < chars.length; i++)
count[chars[i] - 'a']++;
for (int i = 0; i < chars.length; i++)
if (count[chars[i] - 'a'] == 1) return i;
return -1;
}
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
Runtime: 16
ms
public int firstUniqChar(String s) {
int[] count = new int[26];
char[] chars = s.toCharArray();
for (int i = 0; i < chars.length; i++)
count[chars[i] - 'a']++;
for (int i = 0; i < chars.length; i++)
if (count[chars[i] - 'a'] == 1) return i;
return -1;
}
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