PAT 1065. A+B and C (64bit) (20)

         
题目描述：Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C.Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.Output Specification: For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

出题人的本意应该是让我们进行溢出判断，但是这里可以将变量直接定义为long double类型。

#include <iostream>

using namespace std;

int main()
{
long double  a,b;
long double  c;
int n;
cin>>n;
for(int i=0;i<n;i++)
{
cin>>a>>b>>c;
cout<<"Case #"<<i+1<<": ";
if(a-c+b>0)
cout<<"true";
else cout<<"false";
cout<<endl;
}
return 0;
}