POJ-1753-Flip Game

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 39964   Accepted: 17350 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the other one is black and each piece is lying either it's black or white side up. Each round you flip 3 to 5 pieces, thus changing the color of their upper side from black to white and vice versa. The pieces to be flipped are chosen every round according to the following rules:  Choose any one of the 16 pieces.  Flip the chosen piece and also all adjacent pieces to the left, to the right, to the top, and to the bottom of the chosen piece (if there are any). Consider the following position as an example:  bwbw  wwww  bbwb  bwwb  Here "b" denotes pieces lying their black side up and "w" denotes pieces lying their white side up. If we choose to flip the 1st piece from the 3rd row (this choice is shown at the picture), then the field will become:  bwbw  bwww  wwwb  wwwb  The goal of the game is to flip either all pieces white side up or all pieces black side up. You are to write a program that will search for the minimum number of rounds needed to achieve this goal.  Input The input consists of 4 lines with 4 characters "w" or "b" each that denote game field position. Output Write to the output file a single integer number - the minimum number of rounds needed to achieve the goal of the game from the given position. If the goal is initially achieved, then write 0. If it's impossible to achieve the goal, then write the word "Impossible" (without quotes). Sample Input bwwb bbwb bwwb bwww Sample Output 4 Source Northeastern Europe 2000

#include<stdio.h>
#include<queue>
#include<math.h>
#include<string.h>
using namespace std;
bool Map[6][6];
int step = -1, flag = 0;
int tx[] = {1,0,-1,0,0};
int ty[] = {0,1,0,-1,0};
void Filp(int x, int y) // 翻转
{
for(int i = 0; i<5; ++i)
{
int xx = x+tx[i];
int yy = y+ty[i];
Map[xx][yy] = !Map[xx][yy];
}
}
int Make_sure() //判断当前是否为目标状态
{
int k = 0;
for(int i = 1; i<=4; ++i)
for(int j = 1; j<=4; ++j)
k+=Map[i][j];
if(k==16||k==0)return 1;
else return 0;
}
void dfs(int x, int y, int s)
{
if(Make_sure())
{
flag = 1;
if(step>s||step == -1)step = s;
return;
}
if(y>4)
{
++x;
if(x>4)return;
y = 1;
}
dfs(x, y+1, s);
Filp(x, y);
dfs(x, y+1, s+1);
Filp(x, y);

}
int main()
{
char s[5];
for(int i = 1; i<=4; ++i)
{
scanf("%s", s);
for(int j = 1; j<=4; ++j)
{
if(s[j-1]=='b')Map[i][j] = 1;
else Map[i][j] = 0;
}
}
dfs(1, 1, 0);
if(flag)printf("%d\n", step);
else printf("Impossible\n");
return 0;
}