LeetCode 242. Valid Anagram
2016-06-19 10:13
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对俩个字符串各自扫一遍class Solution {
public:
bool isAnagram(string s, string t) {
int len_s=s.length();
int len_t=t.length();
if(len_s!=len_t){
return false;
}
int dp[30];
memset(dp,0,sizeof(dp));
for(string::iterator iter = s.begin();iter != s.end();++iter){
dp[*iter-'a']++;
}
for(string::iterator iter=t.begin();iter!=t.end();iter++){
dp[*iter-'a']--;
}
for(int i=0;i<26;i++){
if(dp[i]){
return false;
}
}
return true;
}
};
public:
bool isAnagram(string s, string t) {
int len_s=s.length();
int len_t=t.length();
if(len_s!=len_t){
return false;
}
int dp[30];
memset(dp,0,sizeof(dp));
for(string::iterator iter = s.begin();iter != s.end();++iter){
dp[*iter-'a']++;
}
for(string::iterator iter=t.begin();iter!=t.end();iter++){
dp[*iter-'a']--;
}
for(int i=0;i<26;i++){
if(dp[i]){
return false;
}
}
return true;
}
};
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