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java.lang.IllegalArgumentException: Service Intent must be explicit: Intent { act=xxx}

2016-06-02 09:55 495 查看
有些时候我们使用Service的时需要采用隐私启动的方式,但是Android 5.0一出来后,其中有个特性就是Service Intent must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。

而android源码是这样写的(源码位置:sdk/sources/android-21/android/app/ContextImpl.java):

private void validateServiceIntent(Intent service) {
if (service.getComponent() == null && service.getPackage() == null) {
if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
IllegalArgumentException ex = new IllegalArgumentException(
"Service Intent must be explicit: " + service);
throw ex;
} else {
Log.w(TAG, "Implicit intents with startService are not safe: " + service
+ " " + Debug.getCallers(2, 3));
}
}
}


既然,源码里是这样写的,那么这里有两种解决方法:

1、设置Action和packageName:

参考代码如下:

Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");//你定义的service的action
mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名
context.startService(mIntent);


此方式是google官方推荐使用的解决方法。

在此附上地址供大家参考:http://developer.android.com/goo … tml#billing-service,有兴趣的可以去看看。

2、将隐式启动转换为显示启动:–参考地址:http://stackoverflow.com/a/26318757/1446

public static Intent getExplicitIntent(Context context, Intent implicitIntent) {

// Retrieve all services that can match the given intent

PackageManager pm = context.getPackageManager();

List resolveInfo = pm.queryIntentServices(implicitIntent, 0);

// Make sure only one match was found

if (resolveInfo == null || resolveInfo.size() != 1) {

return null;

}

// Get component info and create ComponentName

ResolveInfo serviceInfo = resolveInfo.get(0);

String packageName = serviceInfo.serviceInfo.packageName;

String className = serviceInfo.serviceInfo.name;

ComponentName component = new ComponentName(packageName, className);

// Create a new intent. Use the old one for extras and such reuse

Intent explicitIntent = new Intent(implicitIntent);

// Set the component to be explicit

explicitIntent.setComponent(component);

return explicitIntent;

}

调用方式如下:

Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");
Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
context.startService(eintent);
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