您的位置:首页 > 其它

B树的实现

2016-05-07 11:41 351 查看
B树:1970年,R.Bayer和E.mccreight提出了一种适合外查找的树,它是一种平衡的多叉树,称为B树。(有些地方写的是B-树,注意不要误读 成"B减树") 一棵M阶(M>2)的B树,是一棵平衡的M路平衡搜索树,可以是空树或者满足以下性质:

1. 根节点至少有两个孩子

2. 每个非根节点有[ (M/2)向上取整 ,M]个孩子

3. 每个非根节点有[ (M/2)向上取整 -1,M-1]个关键字,并且以升序排列

4. key[i]和key[i+1]之间的孩子节点的值介于key[i]、key[i+1]之间

5. 所有的叶子节点都在同一层

实现代码:
#include<iostream>
using namespace std;

template<class K, int M = 3>
struct BTreeNode
{
K _keys[M];
BTreeNode<K, M>* _subs[M + 1];
size_t _size;
BTreeNode<K, M>* _parent;

BTreeNode()
:_size(0)
, _parent(NULL)
{
for (size_t i = 0; i < M + 1; ++i)
{
_subs[i] = NULL;
}
}
};

template<class K, class V>
struct Pair
{
K _first;
V _second;

Pair(const K& k = K(), const V& v = V())
:_first(k)
, _second(v)
{}
};

template<class K, int M = 3>
class BTree
{
typedef BTreeNode<K, M> Node;
public:
BTree()
:_root(NULL)
{}

Pair<Node*, int> Find(const K& key)
{
Node* parent = NULL;
Node* cur = _root;
while (cur)
{
int i = 0;
while (i < cur->_size && cur->_keys[i] < key)
{
++i;
}
if (cur->_keys[i] == key)
{
return	Pair<Node*, int>(cur, i);
}
parent = cur;
cur = cur->_subs[i];
}
return Pair<Node*, int>(parent, -1);
}

bool Insert(const K& key)
{
if (_root == NULL)
{
_root = new Node;
_root->_keys[0] = key;
++_root->_size;
return true;
}

Pair<Node*, int> ret = Find(key);
if (ret._second != -1)
{
return false;
}
K k = key;
Node *cur = ret._first;
Node *sub = NULL;
while (1)
{
_InsertKey(cur, k, sub);
if (cur->_size < M)
{
return true;
}

int boundary = M / 2;
Node *tmp = new Node;
size_t index = 0;
size_t size = cur->_size;

for (int i = boundary + 1; i < size; ++i)
{
tmp->_keys[index++] = cur->_keys[i];
tmp->_size++;
cur->_size--;
}

index = 0;
for (int i = boundary + 1; i <= size; ++i)
{
tmp->_subs[index] = cur->_subs[i];
if (tmp->_subs[index])
{
tmp->_subs[index]->_parent = tmp;
}
++index;
}

k = cur->_keys[boundary];
cur->_size--;

if (cur->_parent == NULL)
{
_root = new Node;
_root->_keys[0] = k;
_root->_subs[0] = cur;
_root->_subs[1] = tmp;
_root->_size = 1;

tmp->_parent = _root;
cur->_parent = _root;

return true;
}

cur = cur->_parent;
sub = tmp;

}
}

void InOrder()
{
_InOrder(_root);
cout << endl;
}

protected:

void _InsertKey(Node* cur, const K& k, Node* sub)
{
int i = cur->_size - 1;
while (i >= 0)
{
if (cur->_keys[i] > k)
{
cur->_keys[i + 1] = cur->_keys[i];
cur->_subs[i + 2] = cur->_subs[i + 1];
--i;
}
else
{
break;
}
}
cur->_keys[i + 1] = k;
cur->_subs[i + 2] = sub;
if (sub != NULL)
{
sub->_parent = cur;
}
cur->_size++;
}

void _InOrder(Node* root)
{
if (root == NULL)
{
return;
}
for (size_t i = 0; i < root->_size; ++i)
{
_InOrder(root->_subs[i]);
cout << root->_keys[i] << " ";
}
_InOrder(root->_subs[root->_size]);
}

private:
Node* _root;
};

int main()
{
int a[] = { 53, 75, 139, 49, 145, 36, 101 };
BTree<int> bt;
for (int i = 0; i < sizeof(a) / sizeof(a[0]); i++)
{
bt.Insert(a[i]);
}
bt.InOrder();
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: