leetcode 258. Add Digits
2016-05-03 10:05
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My Submissions QuestionEditorial Solution
Total Accepted: 91671 Total Submissions: 189101 Difficulty: Easy
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
Show Hint
Total Accepted: 91671 Total Submissions: 189101 Difficulty: Easy
Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
Show Hint
class Solution {
public:
int addDigits(int num) {
if(num==0)
return 0;
else if(num%9==0)
return 9;
else
return num%9;
}
};
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